JavaScript - Generating Combinations From Dictionary Keys And Keeping Key Names Dynamically
I found this excellent code which generates all the combinations of multiple arrays here: JavaScript - Generating combinations from n arrays with m elements I am now looking to go
Solution 1:
You can convert the array of objects into multi dimensional array. Construct possible combinations and use map
to construct the final format.
var arr = [{"Footprint_Shape": ["L-Shape", "H-Shape", "T-Shape"]}, {"Num_of_Floors": [1, 2]}];
var result = arr.map(o => Object.values(o)[0]) //Convert the array of objects into multi dimensional array.
.reduce((c, v) => [].concat(...c.map(o => v.map(x => [].concat(o, x))))) //Make all possible combinations
.map(([a, b]) => ({"Footprint_Shape": a,"Num_of_Floors": b})) //Construct the final format
console.log(result);
Update:
var arr = [{"Footprint_Shape": ["L-Shape", "H-Shape", "T-Shape"]}, {"Num_of_Floors": [1, 2]}];
var keys = arr.map(o => Object.keys(o)[0]); //Get the list of keys
var result = arr.map(o => Object.values(o)[0]) //Convert the array of objects into multi dimensional array.
.reduce((c, v) => [].concat(...c.map(o => v.map(x => [].concat(o, x))))) //Make all possible combinations
.map(o => o.reduce((c, v, i) => Object.assign(c, {[keys[i]]: v}), {})); //Construct the final format
console.log(result);
Solution 2:
A simple and short alternative:
const [{Footprint_Shape: shapes},{Num_of_Floors: floors} ] = [{"Footprint_Shape":["L-Shape","H-Shape","T-Shape"]},{"Num_of_Floors":[1,2]}];
const result = floors.reduce((all, floor) => {
shapes.forEach(shape => all.push({Footprint_Shape: shape, Num_of_Floors: floor}))
return all;
}, []);
console.log(result);
Solution 3:
let arr = [
{"Footprint_Shape":["L-Shape","H-Shape","T-Shape"]},
{"Num_of_Floors":[1,2]}
]
let answer = [];
arr[0]["Footprint_Shape"].forEach(x => {
arr[1]["Num_of_Floors"].forEach(y => {
let newObj = {};
newObj["Footprint_Shape"] = x;
//console.log('y: ',y)
newObj["Num_of_Floors"] = y
answer.push(newObj);
})
});
console.log(answer)
I think the code should be self explanatory. Using two looping, construct the object and push to a new array
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