Position Div To Center Of Visible Area
I'm in the midst of making a lightbox style pop-up for a mailing list sign up, but I want the pop-up to position to the center of the visible page, not just the center of the whole
Solution 1:
You were close! It can be done with CSS alone:
Use position: fixed
instead of position: absolute
.
Fixed refers to the viewport, while absolute refers to the document. Read all about it!
Solution 2:
var w = $(window).width();
var h = $(window).height();
var d = document.getElementById('my-div');
var divW = $(d).width();
var divH = $(d).height();
d.style.position="absolute";
d.style.top = (h/2)-(divH/2)+"px";
d.style.left = (w/2)-(divW/2)+"px";
Solution 3:
I know this will not solve the question but it is good reference and a starting point: How to position a div in the center of browser window
Position Div Exactly at the center of the screen
<!DOCTYPE html><html ><head><styletype="text/css">.exactCenter {
width:200px;
height:200px;
position: fixed;
background-color: #00FF00;
top: 50%;
left: 50%;
margin-top: -100px;
margin-left: -100px;
}
</style></head><body><divclass="exactCenter"></div></body></html>
JSFiddle here and here
Solution 4:
with jQuery:
var left = ($(window).width() - $(.my-div).width()) / 2;
var top = ($(window).height() - $(.my-div).height()) / 2;
$('.my-div').position({top: top + 'px', left: left + 'px});
Solution 5:
Although the accepted answer is best, if you can't set the divs position
to fixed
, then you can use this pure JavaScript solution.
var myElement = document.getElementById('my-div'),
pageWidth = window.innerWidth,
pageHeight = window.innerHeight,
myElementWidth = myElement.offsetWidth,
myElementHeight = myElement.offsetHeight;
myElement.style.top = (pageHeight / 2) - (myElementHeight / 2) + "px";
myElement.style.left = (pageWidth / 2) - (myElementWidth / 2) + "px";
JSFiddle
Or a more condensed version:
var w = window,
elem = document.getElementById('my-div');
elem.style.top = (w.innerHeight/2) - (elem.offsetHeight/2) + 'px';
elem.style.left = (w.innerWidth/2) - (elem.offsetWidth/2) + 'px';
This answer is a vanilla JavaScript version from Lahiru Ashan's answer.
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